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It is important to see if the element is visible or not as the Driver.FindElement will only check the HTML source. But popup code could be in the page html, and not be visible. Therefore, Driver.FindElement function returns a false positive (and your test will fail)

If the element is present in HTML code then findElement will pass even if the element is hidden. Or say not visible (like a dropdown menu). The question is to find whether element is visible or not.

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For visible check you can use .isDisplayed() method.

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Make sure your window on the remote server is big enough so the elements are not hidden because of space constraints ..

c#
driver.Manage().Window.Size = new System.Drawing.Size(1928, 1060);

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Even though I'm somewhat late answering the question:

You can now use WebElement.isDisplayed() to check if an element is visible.

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public static boolean isElementVisible(final By by)
    throws InterruptedException {
        boolean value = false;

        if (driver.findElements(by).size() > 0) {
            value = true;
        }
        return value;
    }

Not related to the OP, but you can simplify your function. How about: return driver.findElements(by).size() > 0;

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public boolean isPrebuiltTestButtonVisible() {
    try {

        if (preBuiltTestButton.isEnabled()) {

            return true;

        } else {

            return false;
        }

    } catch (Exception e) {

        e.printStackTrace();
        return false;
    }
}

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  • To check Element Present: if(driver.findElements(By.xpath("value")).size() != 0){ System.out.println("Element is Present"); }else{ System.out.println("Element is Absent"); } Or if(driver.findElement(By.xpath("value"))!= null){ System.out.println("Element is Present"); }else{ System.out.println("Element is Absent"); }
  • To check Visible: if( driver.findElement(By.cssSelector("a > font")).isDisplayed()){ System.out.println("Element is Visible"); }else{ System.out.println("Element is InVisible"); }
  • To check Enable: if( driver.findElement(By.cssSelector("a > font")).isEnabled()){ System.out.println("Element is Enable"); }else{ System.out.println("Element is Disabled"); }
  • To check text present if(driver.getPageSource().contains("Text to check")){ System.out.println("Text is present"); }else{ System.out.println("Text is absent"); }

Theses examples would be better using the ExpectedConditions class.

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Even if the element isn't in view(hidden), you can execute javascript on it:

JavascriptExecutor jsx = (JavascriptExecutor)driver;
jsx.executeScript("arguments[0].click();", element);
element

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I think you need to wait for elements before you click especially when you are doing it in a loop. Like others suggested, also try maximizing the window. Probably that will help WebDriver find the co-ordinates of the WebElement accurately, however I am not 100% sure. But I believe that you need WebDriverWait. Give this a try,

WebDriver driver = new FirefoxDriver();
WebDriverWait wait = new WebDriverWait(driver, 300/*seconds*/);
driver.manage().window().maximize();
driver.get("http://www.bbc.com/");
for (int menu_item_module = 0; menu_item_module < 10; menu_item_module++) {
    WebElement element = wait.until(ExpectedConditions.elementToBeClickable(By
                        .id("digitalVellum_dijit_MenuListItem_"
                                +menu_item_module)));
            element.click();
}

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WebElement Check;    
for(int i = 0; i < no; i++)
{
    System.out.println(no);
    Check = checkBoxes.get(r.nextInt(no));
    if(Check.isDisplayed() && Check.isEnabled())
    {
        Check.click();
    }
}

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I have the following 2 suggested ways:

You can use isDisplayed() as below:

You can define a method as below and call it:

Now, you can use assertion as below whether the element is present or not:

assertTrue(isElementPresent(By.id("idOfElement")));

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element instanceof RenderedWebElement

Works, but I still find this a bit annoying. I wonder what the reasoning is for not offering an WebElement.isDisplayed.

This is not working but this interface delegates method isDisplayed and it works. Thanks for the hint. (+1)

Is this still relevant for selenium 2.0? I don't think there is a need for RenderedWebElement (the class itself is gone).

@Eugen I think it has been changed to RemoteWebElement. But yeah as @sleske wrote WebElement.isDisplayed is now available and it probably will work in this use case (I don't have that code available anymore so cannot test).

For real? The question is about specific version of Selenium (2.0a2). So, using isDisplayed() is not a correct answer for the version in question.

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Since WebDriver tries to simulate real users, it cannot interact with elements which are invisible/hidden. To solve your issue, I think you would need to click on div first which will make the drop down visible and select option from the dropdown. I would recommend such an approach as opposed to pure Javascript way since it would simulate a real user. Give following a shot,

WebDriverWait wait = new WebDriverWait(driver, 300);
WebElement triggerDropDown = driver.findElement(By
                .className("ui-helper-hidden"));
triggerDropDown.click();
WebElement selectElement = wait.until(ExpectedConditions
                  .visibilityOfElementLocated(By.id("formLevel:levels_input")));
Select select = new Select(selectElement);
select.selectByVisibleText("SECURITY");

Edit updated the class name of triggerDropDown

I agree with this answer. You wouldn't need to use a FluentWait (ignoring exceptions) on this type of interaction (because the div click has a immediate expected result) and so the WebDriverWait is perfect in this context.

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Here is the one I came up with, but in java. A little drawn out but it walks you through how it should wait. It will take in a wait time in seconds and then check every second to see if the element is present yet. Once it has located the element it makes sure that it is visible so it can be interacted with. "driver" is obviously the WebDriver object.

public void waitForVisible(final By by, int waitTime) {
    wait = new WebDriverWait(driver, timeoutInSeconds);
    for (int attempt = 0; attempt < waitTime; attempt++) {
        try {
            driver.findElement(by);
            break;
        } catch (Exception e) {
            driver.manage().timeouts().implicitlyWait(1, TimeUnit.SECONDS);
        }
    }
    wait.until(ExpectedConditions.visibilityOfElementLocated(by));
}

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Use below function to verify if element is visible on page or not.

isDisplayed()

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To make sure that an element is present you can do the following:

driver.findElements(By.id("id"));

That will return an array, if that array size is > 0 then the element/s is present.

Also, you need to provide more information, such as language and what have you tried before asking,

driver.findelement(By.id("id1")).isDisplayed()' driver.findelement(By.id("id2")).sendkey("test"); Here if element is not displayed it fails test case and is not going on to next step for execution. So please help me how to handle assertion and xcontinue test execution for next steps in selenium webdrier and testng. Even i also want to mark test case fail if anyone assertion is failed.

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If you're using C#, it would be driver.Displayed. Here's an example from my own project:

if (!driver.FindElement(By.Name("newtagfield")).Displayed)      //if the tag options is not displayed
    driver.FindElement(By.Id("expand-folder-tags")).Click();    //make sure the folder and tags options are visible

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You can implement a method which tell you if element is present or not, and based on that you can fail or pass the test cases. There are two way to implement that.

public boolean isElementExist(By identifer, int timeOut){

        WebDriverWait wait = new WebDriverWait(driver, timeOut);

        try{
            wait.until(ExpectedConditions.presenceOfElementLocated(identifer));
            return true;
        }catch (TimeoutException te){
            return false;
        }
    }

And the following is without waiting.

public boolean isElementExit(By identifer){
        return  driver.findElements(identifer).size() > 0;

    }

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Webdriver may throw an ElementNotVisible exception in-case there are multiple elements with the same locator and if Webdriver has already operated upon one of the element matching the locator.

In such scenarios you can first get the size of the element using

int var_ele_size= driver.findElements(By.xpath("locator")).size();

and then take the first element from the list and click on the element.

driver.findElements(By.xpath("locator")).get(var_ele_size-1).click();

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